stephanie2566 stephanie2566
  • 02-08-2018
  • Mathematics
contestada

4. Suppose an investment of $s1.800 doubles in value every 7 years. How much is the investment worth after 42 years?

Respuesta :

rejkjavik rejkjavik
  • 02-08-2018

we are given

initial amount =1800

so,

P=1800

doubles in value every 7 years

so, we can find function

[tex] A=P(2)^{\frac{t}{7} } [/tex]

now, we can plug P=1800

[tex] A=1800(2)^{\frac{t}{7} } [/tex]

now, we can plug t=42

[tex] A=1800(2)^{\frac{42}{7} } [/tex]

[tex] A=115200 [/tex].............Answer

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