Sabercat4life Sabercat4life

02-05-2020
Mathematics

contestada

Anyone I’m really lost

Anyone Im really lost class=

Respuesta :

CHERLYNnotCHERRY CHERLYNnotCHERRY

02-05-2020

Answer:

The answer is option 3.

Step-by-step explanation:

You have to substitute H+=2×10^(-9) into the equation of pH :

pH = -log[H+]

H+ = 2×10^(-9)

pH = -log[2×10^-9]

= 8.70 (3s.f)

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