Answer:
n(7n +8)(n^2 +10)
Step-by-step explanation:
n is obviously a factor of every term. We also note that pairs of terms have coefficients in the ratio of 7 : 8, so (7n +8) is another factor.
56n^4 +64n^3 +70n^2 +80n = n((7n +8)n^2 +(7n +8)·10)
Then the factorization in integers is ...
= n(7n +8)(n^2 +10)
