Answer:
[tex]Solution,\\m<KJM +m<JML = 180^o [Sum~of~cointerior~angles~is~180^o.]\\or, 56^o +m<LJM +27^o+72^o = 180^o\\or, m<LJM +155^o=180^o\\or, m<LJM = 25^o[/tex]
JKLM is a parallelogram
=> JK // LM
=> KJM + LMJ = 180⁰
<=> 56⁰ + LJM + 72⁰ + 27⁰ = 180⁰
=> LJM = 180⁰ - 56⁰ - 72⁰ - 27⁰ = 25⁰
