guadalupeperez1 guadalupeperez1
  • 02-12-2017
  • Mathematics
contestada

Solve each quadratic equation using the Quadratic Formula.

Solve each quadratic equation using the Quadratic Formula class=

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astroprincess331
astroprincess331 astroprincess331
  • 02-12-2017
x=-4+-√4²-4(5)(0)
------------------------
           2(5)

x=-4+-16
------------
     10


-20
----
10  

x=-2

-4+16
---------
   10

x=1.2
Answer Link
chetankachana
chetankachana chetankachana
  • 07-07-2022

Answer:

[tex]x = -\frac45, x = 0[/tex]

Step-by-step explanation:

Hello!

To solve this, we have to simplify the radical and fraction.

Simplify:

  • [tex]x = \frac{-4 \pm\sqrt{4^2 - 4(5)(0)}}{2(5)}[/tex]
  • [tex]x = \frac{-4 \pm \sqrt{16}}{10}[/tex]
  • [tex]x = \frac{-4 \pm 4}{10}[/tex]
  • [tex]x = -\frac45, x = 0[/tex]

There are two solutions for x: -0.8, and 0.

Answer Link

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