01-05-2016
Mathematics

contestada

the zeros of the function f(x) =(x+2) to the second power minus 5

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konrad509 konrad509

01-05-2016

[tex](x+2)^2-5=0\\ (x+2)^2=5\\ x+2=-\sqrt5 \vee x+2=\sqrt5\\ x=-2-\sqrt5 \vee x=-2+\sqrt5[/tex]

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