TastesLikeSkittles
TastesLikeSkittles TastesLikeSkittles
  • 04-02-2020
  • Mathematics
contestada

Solve sin theta + 1 = cos2 theta on the interval

Solve sin theta 1 cos2 theta on the interval class=

Respuesta :

Hrishii
Hrishii Hrishii
  • 04-02-2020

Step-by-step explanation:

Hope it helps you in your learning process.

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Answer Link
SilverChain SilverChain
  • 04-02-2020

Answer:

Θ = 0, [tex]\frac{7\pi }{6}[/tex], [tex]\frac{11\pi }6}[/tex]

Step-by-step explanation:

sin(theta) + 1 = cos^2(theta) - sin^2(theta)

sin(theta) + 1 = (1 - sin^2(theta)) -sin^2(theta)

sin(theta) = -2sin^2(theta)

2sin^2(theta) + sin(theta) = 0

sin(theta)[2sin(theta) + 1] = 0

sin(theta) = 0 and 2sin(theta) + 1 = 0

sin(theta) = 0 and sin(theta) = -1/2

Θ = 0, [tex]\frac{7\pi }{6}[/tex], [tex]\frac{11\pi }6}[/tex]

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