Answer:
0.3M
Explanation:
Molarity of a solution is given by;
M=n/v
Where;
n= number of moles of solute = mass of solute / molar mass
v= volume of solution
n= mass of CaCl2 / molar mass of CaCl2
Mass of CaCl2 = 0.5
Molar mass of CaCl2 = 40 + (2×35.5)
= 111g/mol
n = 0.5/111 = 0.0045mol
volume, v= 15mL = 15/1000 L = 0.015L
Note that molarity is in mole per liter, hence we convert 15mL to L. 1mL=1/1000L
M =0.0045/0.015
M=0.3mol/L
Therefore, the molarity of the solution is 0.3M
