faithsmith69 faithsmith69

14-05-2020
Mathematics

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find the zeros of the function f(x)=8x^2 +32

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Snowphie101 Snowphie101

16-05-2020

Answer: no solution

Step-by-step explanation:

[tex]8x^{2} +32=0[/tex]

Factor out 8

[tex]8(x^{2} +4)=0[/tex]

no solution

Why?

Think about the graph, [tex]x^{2}[/tex] shifted up 4 has no zeros, even with a vertical stretch of 8.

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