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04-01-2022
Mathematics

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The absolute maximum value of f(x)= x^3– 3x^2 +12 on the closed interval [-2, 4] occurs at x =

A.4
B.2
C.1
D.0
E.-2

Respuesta :

Yessnialorhanod7 Yessnialorhanod7

04-01-2022

The answer to this equation is -2

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