The factor of 9x^2−49y^2 is (3x + 7y)(3x - 7y)
Difference of to square
According to the differnce of two square:
Given the expression 9x^2−49y^2
This can be further expressed as:
(3x)^2 - (7y)^2
Let a = 3x and b = 7y
Applying the rule, we will have:
9x^2−49y^2 = (3x + 7y)(3x - 7y)
Hence the factor of 9x^2−49y^2 is (3x + 7y)(3x - 7y)
Learn more on Difference of to square here: https://brainly.com/question/1123986
